Function leafCount #

Gives the number of “leaf nodes” in the parse tree of the given expression A leaf node is one that has no subexpressions, essentially either a symbol or a constant. Note that 5! has just one leaf, the ‘5’; the unary factorial operator does not add a leaf. On the other hand, function symbols do add leaves, so sin(x)/cos(x) has four leaves.

The simplify() function should generally not increase the leafCount() of an expression, although currently there is no guarantee that it never does so. In many cases, simplify() reduces the leaf count.

Syntax #


Parameters #

Parameter Type Description
expr Node | string The expression to count the leaves of

Returns #

Type Description
number The number of leaves of expr

Throws #

Type | Description —- | ———–

Examples #

math.leafCount('x') // 1
math.leafCount(math.parse('a*d-b*c')) // 4
math.leafCount('[a,b;c,d][0,1]') // 6

See also #


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