Function resolve #
resolve(expr, scope) replaces variable nodes with their scoped values
Syntax #
math.resolve(expr, scope)
Parameters #
| Parameter |
Type |
Description |
node |
Node | Node[] |
The expression tree (or trees) to be simplified |
scope |
Object |
Scope specifying variables to be resolved |
Returns #
| Type |
Description |
| Node | Node[] |
Returns node with variables recursively substituted. |
Throws #
| Type |
Description |
| ReferenceError |
If there is a cyclic dependency among the variables in scope, resolution is impossible and a ReferenceError is thrown. |
Examples #
math.resolve('x + y', {x:1, y:2}) // Node '1 + 2'
math.resolve(math.parse('x+y'), {x:1, y:2}) // Node '1 + 2'
math.simplify('x+y', {x:2, y: math.parse('x+x')}).toString() // "6"
See also #
simplify,
evaluate
